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BNAndrasBNAndras
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Add diamond (#371)
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‎config.json

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"prerequisites": [],
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"difficulty": 5
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},
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{
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"slug": "diamond",
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"name": "Diamond",
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"uuid": "f1da1920-802f-4165-87a4-2381f530c262",
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"practices": [],
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"prerequisites": [],
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"difficulty": 5
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},
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{
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"slug": "house",
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"name": "House",

‎exercises/practice/diamond/.docs/instructions.md

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# Instructions
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The diamond kata takes as its input a letter, and outputs it in a diamond shape.
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Given a letter, it prints a diamond starting with 'A', with the supplied letter at the widest point.
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## Requirements
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- The first row contains one 'A'.
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- The last row contains one 'A'.
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- All rows, except the first and last, have exactly two identical letters.
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- All rows have as many trailing spaces as leading spaces. (This might be 0).
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- The diamond is horizontally symmetric.
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- The diamond is vertically symmetric.
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- The diamond has a square shape (width equals height).
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- The letters form a diamond shape.
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- The top half has the letters in ascending order.
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- The bottom half has the letters in descending order.
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- The four corners (containing the spaces) are triangles.
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## Examples
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In the following examples, spaces are indicated by `·` characters.
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Diamond for letter 'A':
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```text
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A
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```
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Diamond for letter 'C':
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```text
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··A··
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·B·B·
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C···C
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·B·B·
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··A··
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```
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Diamond for letter 'E':
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```text
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····A····
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···B·B···
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··C···C··
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·D·····D·
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E·······E
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·D·····D·
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··C···C··
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···B·B···
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····A····
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```

‎exercises/practice/diamond/.meta/config.json

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{
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"authors": [
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"BNAndras"
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],
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"files": {
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"solution": [
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"diamond.coffee"
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],
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"test": [
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"diamond.spec.coffee"
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],
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"example": [
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".meta/example.coffee"
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]
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},
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"blurb": "Given a letter, print a diamond starting with 'A' with the supplied letter at the widest point.",
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"source": "Seb Rose",
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"source_url": "https://web.archive.org/web/20220807163751/http://claysnow.co.uk/recycling-tests-in-tdd/"
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}

‎exercises/practice/diamond/.meta/example.coffee

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class Diamond
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@rows: (letter) ->
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return 'A' if letter is 'A'
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start = 'A'.charCodeAt 0
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end = letter.charCodeAt 0
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size = end - start + 1
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diamond = []
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# Down to middle of diamond
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for i in [0...size]
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currentChar = String.fromCharCode start + i
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outer = ' '.repeat size - 1 - i
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if i is 0
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line = outer + currentChar + outer
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else
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inner = ' '.repeat 2 * i - 1
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line = outer + currentChar + inner + currentChar + outer
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diamond.push line
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# flip the diamond to make the bottom half
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for i in [size-2..0]
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diamond.push diamond[i]
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diamond.join '\n'
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module.exports = Diamond

‎exercises/practice/diamond/.meta/tests.toml

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# This is an auto-generated file.
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#
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# Regenerating this file via `configlet sync` will:
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# - Recreate every `description` key/value pair
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# - Recreate every `reimplements` key/value pair, where they exist in problem-specifications
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# - Remove any `include = true` key/value pair (an omitted `include` key implies inclusion)
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# - Preserve any other key/value pair
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#
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# As user-added comments (using the # character) will be removed when this file
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# is regenerated, comments can be added via a `comment` key.
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[202fb4cc-6a38-4883-9193-a29d5cb92076]
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description = "Degenerate case with a single 'A' row"
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[bd6a6d78-9302-42e9-8f60-ac1461e9abae]
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description = "Degenerate case with no row containing 3 distinct groups of spaces"
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[af8efb49-14ed-447f-8944-4cc59ce3fd76]
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description = "Smallest non-degenerate case with odd diamond side length"
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[e0c19a95-9888-4d05-86a0-fa81b9e70d1d]
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description = "Smallest non-degenerate case with even diamond side length"
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[82ea9aa9-4c0e-442a-b07e-40204e925944]
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description = "Largest possible diamond"

‎exercises/practice/diamond/diamond.coffee

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class Diamond
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@rows: (letter) ->
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module.exports = Diamond

‎exercises/practice/diamond/diamond.spec.coffee

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Diamond = require './diamond'
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describe 'Diamond', ->
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it 'Degenerate case with a single A row', ->
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expected = [
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'A'
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].join '\n'
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expect(Diamond.rows 'A').toEqual expected
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xit 'Degenerate case with no row containing 3 distinct groups of spaces', ->
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expected = [
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' A '
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'B B'
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' A '
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].join '\n'
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expect(Diamond.rows 'B').toEqual expected
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xit 'Smallest non-degenerate case with odd diamond side length', ->
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expected = [
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' A '
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' B B '
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'C C'
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' B B '
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' A '
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].join '\n'
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expect(Diamond.rows 'C').toEqual expected
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xit 'Smallest non-degenerate case with even diamond side length', ->
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expected = [
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' A '
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' B B '
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' C C '
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'D D'
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' C C '
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' B B '
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' A '
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].join '\n'
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expect(Diamond.rows 'D').toEqual expected
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xit 'Largest possible diamond', ->
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expected = [
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' A '
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' B B '
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' C C '
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' D D '
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' E E '
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' F F '
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' G G '
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' H H '
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' I I '
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' J J '
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' K K '
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' L L '
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' M M '
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' N N '
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' O O '
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' P P '
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' Q Q '
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' R R '
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' S S '
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' T T '
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' U U '
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' V V '
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' W W '
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' X X '
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' Y Y '
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'Z Z'
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' Y Y '
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' X X '
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' W W '
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' V V '
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' U U '
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' T T '
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' S S '
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' R R '
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' Q Q '
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' P P '
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' O O '
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' N N '
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' M M '
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' L L '
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' K K '
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' J J '
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' I I '
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' H H '
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' G G '
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' F F '
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' E E '
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' D D '
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' C C '
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' B B '
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' A '
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].join '\n'
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expect(Diamond.rows 'Z').toEqual expected

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