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Merge pull request #74 from meilune/master
Translated IF statements article and tasks
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**Yes, it will.**
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**Taip, bus.**
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Any string except an empty one (and `"0"` is not empty) becomes `true` in the logical context.
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Bet kokia eilutė išskyrus tuščią (o `"0"` nėra tuščia) tampa `true` loginiame kontekste.
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We can run and check:
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Mes galime paleisti ir patikrinti:
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```js run
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if ("0") {
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alert( 'Hello' );
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alert( 'Labas' );
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}
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```
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1-js/02-first-steps/10-ifelse/1-if-zero-string/task.md

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---
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# if (a string with zero)
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# if (eilutė su nuliu)
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Will `alert` be shown?
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Ar bus parodytas `alert`?
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```js
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if ("0") {
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alert( 'Hello' );
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alert( 'Labas' );
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}
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```
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Loading

1-js/02-first-steps/10-ifelse/2-check-standard/ifelse_task2/index.html

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<script>
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'use strict';
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let value = prompt('What is the "official" name of JavaScript?', '');
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let value = prompt('Koks yra "oficialus JavaScript pavadinimas?', '');
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if (value == 'ECMAScript') {
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alert('Right!');
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alert('Teisingai!');
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} else {
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alert("You don't know? ECMAScript!");
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alert("Nežinote? ECMAScript!");
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}
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</script>
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1-js/02-first-steps/10-ifelse/2-check-standard/task.md

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---
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# The name of JavaScript
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# JavaScript pavadinimas
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Using the `if..else` construct, write the code which asks: 'What is the "official" name of JavaScript?'
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Naudodami konstruktą `if..else`, parašykite kodą, kuris klausia: 'Koks yra "oficialus JavaScript pavadinimas?'
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If the visitor enters "ECMAScript", then output "Right!", otherwise -- output: "Didn't know? ECMAScript!"
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Jeigu lankytojas įveda "ECMAScript", tada gaunamas "Teisingai!", kitu atveju -- gaunamas: "Nežinojote? ECMAScript!"
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![](ifelse_task2.svg)
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1-js/02-first-steps/10-ifelse/3-sign/if_sign/index.html

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<script>
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'use strict';
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let value = prompt('Type a number', 0);
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let value = prompt('Įrašykite skaičių', 0);
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if (value > 0) {
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alert(1);

1-js/02-first-steps/10-ifelse/3-sign/solution.md

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```js run
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let value = prompt('Type a number', 0);
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let value = prompt('Įveskite skaičių', 0);
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if (value > 0) {
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alert( 1 );

1-js/02-first-steps/10-ifelse/3-sign/task.md

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---
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# Show the sign
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# Parodykite ženklą
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Using `if..else`, write the code which gets a number via `prompt` and then shows in `alert`:
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Naudodami `if..else`, parašykite kodą, kuris gauna numerį per `prompt` ir tada parodo jį per `alert`:
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- `1`, if the value is greater than zero,
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- `-1`, if less than zero,
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- `0`, if equals zero.
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- `1`, jeigu vertė yra didesnė nei nulis,
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- `-1`, jeigu mažesnė nei nulis,
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- `0`, jeigu lygus nuliui.
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In this task we assume that the input is always a number.
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Šioje užduotyje mes tariame, kad visada yra įvedamas numeris.
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[demo src="if_sign"]
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```js
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let result = (a + b < 4) ? 'Below' : 'Over';
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let result = (a + b < 4) ? 'Žemiau' : 'Aukščiau';
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```
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1-js/02-first-steps/10-ifelse/5-rewrite-if-question/task.md

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---
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# Rewrite 'if' into '?'
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# Perrašykite 'if' į '?'
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Rewrite this `if` using the conditional operator `'?'`:
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Perrašykite šį `if` naudodami sąlygos operatorių `'?'`:
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```js
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let result;
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if (a + b < 4) {
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result = 'Below';
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result = 'Žemiau';
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} else {
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result = 'Over';
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result = 'Aukščiau';
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}
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```
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```js
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let message = (login == 'Employee') ? 'Hello' :
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(login == 'Director') ? 'Greetings' :
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(login == '') ? 'No login' :
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let message = (login == 'Darbuotojas') ? 'Labas' :
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(login == 'Direktorius') ? 'Sveiki' :
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(login == '') ? 'Nėra prisijungimo' :
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'';
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```
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1-js/02-first-steps/10-ifelse/6-rewrite-if-else-question/task.md

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---
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# Rewrite 'if..else' into '?'
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# Perrašykite 'if..else' į '?'
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Rewrite `if..else` using multiple ternary operators `'?'`.
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Perrašykite `if..else` naudodami daugybinius ternarinius operatorius `'?'`.
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For readability, it's recommended to split the code into multiple lines.
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Dėl skaitomo rekomenduoja išskirti kodą į kelias eiles.
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```js
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let message;
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if (login == 'Employee') {
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message = 'Hello';
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} else if (login == 'Director') {
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message = 'Greetings';
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if (login == 'Darbuotojas') {
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message = 'Labas';
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} else if (login == 'Direktorius') {
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message = 'Sveiki';
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} else if (login == '') {
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message = 'No login';
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message = 'Nėra prisijungimo';
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} else {
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message = '';
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}

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