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max() over itertools.ifilter() is broken in 0.18.0 #510

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@xeron

Description

@xeron

Python 2.7.16.
macOS 10.14.6.

Reproducible with:

import builtins
import operator

from itertools import ifilter
from random import shuffle


class Backend(object):
    def __init__(self, priority):
        super(Backend, self).__init__()
        self.priority = priority


def max(*args, **kwargs):
    """
    Add support for 'default' kwarg.

    >>> max([], default='res')
    'res'

    >>> max(default='res')
    Traceback (most recent call last):
    ...
    TypeError: ...

    >>> max('a', 'b', default='other')
    'b'
    """
    missing = object()
    default = kwargs.pop('default', missing)
    try:
        mmax = builtins.max(*args, **kwargs)
        return mmax
    except ValueError as exc:
        if 'empty sequence' in str(exc) and default is not missing:
            return default
        raise


by_priority = operator.attrgetter('priority')

backends = [Backend(5), Backend(1), Backend(0.5), Backend(0.6)]

while True:
    shuffle(backends)
    filtered_backends = ifilter(None, backends)
    max_object = max(filtered_backends, key=by_priority)
    print(max_object.priority)
    if max_object.priority != 5:
        exit(1)

Can't reproduce with 0.17.1.

This affects older versions of keyring library using similar code to select keychain backend where it wants max priority backend but returns the wrong one.

Also it looks like it depends on the order of the list.

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