Created problem_39 in project_euler

project_euler/problem_39/__init__.py

@@ -0,0 +1 @@
+#

project_euler/problem_39/sol1.py

@@ -0,0 +1,42 @@
+"""
+If p is the perimeter of a right angle triangle with integral length sides,
+{a,b,c}, there are exactly three solutions for p = 120.
+{20,48,52}, {24,45,51}, {30,40,50}
+
+For which value of p ≤ 1000, is the number of solutions maximised?
+"""
+
+from typing import Dict
+from collections import Counter
+
+
+def pythagorean_triple(max_perimeter: int) -> Dict:
+    """
+    Returns a dictionary with keys as the perimeter of a right angled triangle
+    and value as the number of corresponding triplets.
+    >>> pythagorean_triple(15)
+    Counter({12: 1})
+    >>> pythagorean_triple(40)
+    Counter({12: 1, 30: 1, 24: 1, 40: 1, 36: 1})
+    >>> pythagorean_triple(50)
+    Counter({12: 1, 30: 1, 24: 1, 40: 1, 36: 1, 48: 1})
+    """
+    triplets = Counter()
+    for base in range(1, max_perimeter + 1):
+        for perpendicular in range(base, max_perimeter + 1):
+            hypotenuse = (base * base + perpendicular * perpendicular) ** 0.5
+            if hypotenuse == int((hypotenuse)):
+                perimeter = int(base + perpendicular + hypotenuse)
+                if perimeter > max_perimeter:
+                    continue
+                else:
+                    if perimeter in triplets:
+                        triplets[perimeter] += 1
+                    else:
+                        triplets[perimeter] = 1
+    return triplets
+
+
+if __name__ == "__main__":
+    triplets = pythagorean_triple(1000)
+    print(max(triplets, key=lambda key: triplets[key]))