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Serial.println("'\n'); causes stack overflow #2665

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@tjnomad

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@tjnomad

this statement: Serial.println("'\n');

causes a stack overflow. Obviously the missing " is not caught before the line ends!

Your welcome ...TJ

TJ Schmidt: entrepreneur, scientist, creator of wonderful stuff!

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    Component: PreprocessorThe Arduino sketch preprocessor converts .ino files into C++ code before compilation

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