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Pull Request Template
Description
Given an array nums and a value val, remove all instances of that value in-place and return the new length.
Approach involves using two pointers (fast and slow). Iterate through the array with the fast pointer, if the value at fast does not match the value, then we just need to swap value of the slow pointer with the fast pointer. We can then increment slow pointer after each swap (fast pointer is incremented after each iteration). At the end, the array is modified in place and effectively all occurrences of the 'value' is moved to the end of the array. The value of 'slow' gives the length of the modified array where there are no occurrences of 'value'.
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How Has This Been Tested?
Please describe the tests that you ran to verify your changes. Please also note any relevant details for your test configuration.
Accepted Solution on LeetCode
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