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cmd/go: go build should honor umask #12692

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@0xmohit

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@0xmohit

No matter what the umask, go build would always create a binary with perms 0755.

$  ( umask 0022; go build -o foo foo.go ; ls -l foo )
-rwxr-xr-x 1 ubuntu ubuntu 2848496 Sep 19 12:00 foo
$  ( umask 0000; go build -o foo foo.go ; ls -l foo )
-rwxr-xr-x 1 ubuntu ubuntu 2848496 Sep 19 12:00 foo
$  ( umask 0077; go build -o foo foo.go ; ls -l foo )
-rwxr-xr-x 1 ubuntu ubuntu 2848496 Sep 19 12:00 foo

Compilers (including gcc, ghc, dmd) usually respect umask while creating executables.

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