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Description
There's a place in std::is_permutation
where we eliminate a common prefix at the start. We could use std::mismatch
instead of a hand-written loop, since mismatch
is vectorized.
Inside __is_permutation_impl
, we can use std::find
for "Have we already counted the number of *__i
in [f1, l1)
?"
In the main loop of __is_permutation_impl
, we can basically use std::count
to count the number of times a value appears, I think.