Description
Code Sample, a copy-pastable example if possible
p = pd.Period('2000-01-01 00:00:00.123456789', freq='N')
print(p.freq)
print(p)
print(p + pd.Timedelta(789, 'ns'))This results in:
<Nano>
2000-01-01 00:00:00.123456000
2000-01-01 00:00:00.123456789
Problem description
From my reading of the docs, it appears that Period objects should accept nanosecond input, and they appear to support it, above, using Timedeltas.
The problem is that it appears to truncate the input strings.
Expected Output
<Nano>
2000-01-01 00:00:00.123456789
2000-01-01 00:00:00.123457578
Output of pd.show_versions()
INSTALLED VERSIONS
commit: None
python: 2.7.6.final.0
python-bits: 64
OS: Darwin
OS-release: 15.6.0
machine: x86_64
processor: i386
byteorder: little
LC_ALL: None
LANG: en_US.UTF-8
LOCALE: None.None
pandas: 0.20.3
pytest: None
pip: 9.0.1
setuptools: 21.0.0
Cython: 0.24
numpy: 1.13.1
scipy: 0.18.0.dev0+46034f7
xarray: None
IPython: 5.0.0b4
sphinx: 1.4.4
patsy: 0.2.1
dateutil: 2.2
pytz: 2016.4
blosc: None
bottleneck: None
tables: None
numexpr: 2.4
feather: None
matplotlib: 2.0.0rc2
openpyxl: 1.8.6
xlrd: 0.9.2
xlwt: None
xlsxwriter: None
lxml: 3.4.0
bs4: 4.3.2
html5lib: None
sqlalchemy: 1.0.14
pymysql: None
psycopg2: 2.6.1 (dt dec pq3 ext lo64)
jinja2: 2.8
s3fs: None
pandas_gbq: None
pandas_datareader: 0.2.1