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Series[Period] +/- NaT returns Series[datetime64] #19389

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@jbrockmendel

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@jbrockmendel
per = pd.Period('2016Q1')
ser = pd.Series([per])

>>> ser - pd.NaT
0   NaT
dtype: datetime64[ns]

>>> ser + pd.NaT
0   NaT
dtype: datetime64[ns]

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    BugMissing-datanp.nan, pd.NaT, pd.NA, dropna, isnull, interpolateNumeric OperationsArithmetic, Comparison, and Logical operationsPeriodPeriod data typeTimedeltaTimedelta data type

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