Closed
Description
Can we break API here to return a Series[Sparse] instead?
In [12]: df = pd.DataFrame({"A": pd.SparseArray([1, 2, 3])})
In [13]: df.dtypes
Out[13]:
A Sparse[int64, 0]
dtype: object
In [14]: type(df['A'])
Out[14]: pandas.core.sparse.series.SparseSeries
cc @rkern