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Regression in 0.24: to_timedelta handling of float values #25077

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@Sup3rGeo

Description

@Sup3rGeo

Code Sample, a copy-pastable example if possible

Creating an TimedeltaIndex with 1 microsecond steps:

import pandas as pd
import scipy as sp
t = sp.arange(0,1,1e-6)
index = pd.to_timedelta(t, unit='s')

Problem description

Output in 0.24:

image

We have repeated index values (e.g. 99992 in the image) and missing ones (e.g. 99994 in the image).

This looks like some sort of rounding issue.

Expected Output

Output in 0.23.4:

image

In this version everything is okay.

Output of pd.show_versions()

pd.show_versions()

INSTALLED VERSIONS

commit: None
python: 3.6.7.final.0
python-bits: 64
OS: Windows
OS-release: 10
machine: AMD64
processor: Intel64 Family 6 Model 58 Stepping 9, GenuineIntel
byteorder: little
LC_ALL: None
LANG: None
LOCALE: None.None

pandas: 0.24.0
pytest: 4.1.0
pip: 18.1
setuptools: 39.0.1
Cython: 0.29.2
numpy: 1.15.4
scipy: 1.1.0
pyarrow: 0.11.1
xarray: 0.11.2
IPython: 7.2.0
sphinx: 1.8.3
patsy: None
dateutil: 2.7.5
pytz: 2018.7
blosc: 1.7.0
bottleneck: 1.2.1
tables: 3.4.4
numexpr: 2.6.9
feather: None
matplotlib: 3.0.2
openpyxl: 2.5.12
xlrd: 1.2.0
xlwt: 1.3.0
xlsxwriter: 1.1.2
lxml.etree: 4.3.0
bs4: 4.7.1
html5lib: 1.0.1
sqlalchemy: 1.2.15
pymysql: None
psycopg2: None
jinja2: 2.10
s3fs: 0.2.0
fastparquet: 0.2.1
pandas_gbq: None
pandas_datareader: None
gcsfs: None

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    RegressionFunctionality that used to work in a prior pandas versionTimedeltaTimedelta data type

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