Closed
Description
Code Sample, a copy-pastable example if possible
from datetime import datetime, timezone
import pandas as pd
dt1 = pd.to_datetime(datetime(2020, 3, 11), utc=True)
print(repr(dt1))
print(type(dt1.tz))
dt2 = pd.to_datetime(datetime(2020, 3, 11, tzinfo=timezone.utc))
print(repr(dt2))
print(type(dt2.tz))
# dragons here
print(dt1 - dt2)
outputs
Timestamp('2020-03-11 00:00:00+0000', tz='UTC')
<class 'pytz.UTC'>
Timestamp('2020-03-11 00:00:00+0000', tz='UTC')
<class 'datetime.timezone'>
TypeError: Timestamp subtraction must have the same timezones or no timezones
Problem description
There is no ability to specify which "UTC" the Timestamp should be. I suggest extending the interface of pd.to_datetime()
to specify utc_cls=pytz.UTC
.
Expected Output
Output of pd.show_versions()
INSTALLED VERSIONS
------------------
commit : None
python : 3.7.5.final.0
python-bits : 64
OS : Linux
OS-release : 5.3.0-40-generic
machine : x86_64
processor : x86_64
byteorder : little
LC_ALL : None
LANG : en_US.UTF-8
LOCALE : en_US.UTF-8
pandas : 1.0.1
numpy : 1.17.4
pytz : 2019.2
dateutil : 2.7.3
pip : 19.3.1
setuptools : 42.0.1
Cython : 0.29.14
pytest : 5.3.1
hypothesis : None
sphinx : None
blosc : None
feather : None
xlsxwriter : None
lxml.etree : 4.5.0
html5lib : None
pymysql : None
psycopg2 : 2.8.4 (dt dec pq3 ext lo64)
jinja2 : 2.10.3
IPython : 7.10.0
pandas_datareader: None
bs4 : 4.8.1
bottleneck : None
fastparquet : None
gcsfs : None
lxml.etree : 4.5.0
matplotlib : 3.1.2
numexpr : None
odfpy : None
openpyxl : None
pandas_gbq : None
pyarrow : 0.16.0
pytables : None
pytest : 5.3.1
pyxlsb : None
s3fs : None
scipy : 1.2.1
sqlalchemy : 1.3.12
tables : None
tabulate : None
xarray : None
xlrd : None
xlwt : None
xlsxwriter : None
numba : None