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DOC: update the pandas.Series.dt.dayofweek docstring #20230
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Original file line number | Diff line number | Diff line change |
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@@ -1707,8 +1707,67 @@ def freq(self, value): | |
weekofyear = _field_accessor('weekofyear', 'woy', | ||
"The week ordinal of the year") | ||
week = weekofyear | ||
dayofweek = _field_accessor('dayofweek', 'dow', | ||
"The day of the week with Monday=0, Sunday=6") | ||
_dayofweek_doc = """ | ||
The day of the week with Monday=0, Sunday=6. | ||
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Return the day of the week. It is assumed the week starts on | ||
Monday, which is denoted by 0 and ends on Sunday which is denoted | ||
by 6. This method is available on both Series with datetime | ||
values or DatetimeIndex | ||
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See Also | ||
-------- | ||
pandas.Series.dt.dayofweek : Identical method. | ||
pandas.Series.dt.weekday : Identical method. | ||
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Returns | ||
------- | ||
ndarray | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. these return an Index |
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Containing integers indicating the day number. | ||
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Examples | ||
-------- | ||
>>> dates = pd.date_range("2016-12-31", "2017-01-08", freq="D") | ||
>>> s = pd.Series(dates) | ||
>>> day_name = s.dt.strftime("%A") | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. we have a method There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. did not know this. i was confused because i saw There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. change the code here as well and simply use |
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>>> pd.DataFrame({'dt': s, 'num': s.dt.weekday, 'day': day_name}) | ||
dt num day | ||
0 2016-12-31 5 Saturday | ||
1 2017-01-01 6 Sunday | ||
2 2017-01-02 0 Monday | ||
3 2017-01-03 1 Tuesday | ||
4 2017-01-04 2 Wednesday | ||
5 2017-01-05 3 Thursday | ||
6 2017-01-06 4 Friday | ||
7 2017-01-07 5 Saturday | ||
8 2017-01-08 6 Sunday | ||
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Note: `pandas.Series.dt.dayofweek`/`pandas.Series.dt.weekday` are the same. | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. you are operating on an Index here (and the doc-string goes for both) There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. @jreback could you elaborate? im not sure what you mean with that. There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. ignore my comment here |
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>>> s.dt.dayofweek | ||
0 5 | ||
1 6 | ||
2 0 | ||
3 1 | ||
4 2 | ||
5 3 | ||
6 4 | ||
7 5 | ||
8 6 | ||
dtype: int64 | ||
>>> s.dt.weekday | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. you don't need to show both, just use dayofweek |
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0 5 | ||
1 6 | ||
2 0 | ||
3 1 | ||
4 2 | ||
5 3 | ||
6 4 | ||
7 5 | ||
8 6 | ||
dtype: int64 | ||
""" | ||
dayofweek = _field_accessor('dayofweek', 'dow', _dayofweek_doc) | ||
weekday = dayofweek | ||
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weekday_name = _field_accessor( | ||
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you can say alias
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add day_name as well
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I've changed it into this now.
Note that the docstring for
dayofweek
andweekday
is the exact same.