Closed
Description
This stack overflow question shows that if one tries to declare a FnOnce<(T, U), Output=V>
(which should be a FnOnce(T, U) -> V
), the error message is quite misleading.
This stack overflow question shows that if one tries to declare a FnOnce<(T, U), Output=V>
(which should be a FnOnce(T, U) -> V
), the error message is quite misleading.