Skip to content

NLL suggests removing mutability from a variable, doing so causes a compiler error  #47279

Closed
@shepmaster

Description

@shepmaster

UPDATE: Mentoring instructions below.


This code compiles, but with a warning:

#![feature(nll)]

#[derive(Debug)]
struct A {}

fn init_a() -> A {
    A {}
}

#[derive(Debug)]
struct B<'a> {
    ed: &'a mut A,
}

fn init_b<'a>(ed: &'a mut A) -> B<'a> {
    B { ed }
}

#[derive(Debug)]
struct C<'a> {
    pd: &'a mut B<'a>,
}

fn init_c<'a>(pd: &'a mut B<'a>) -> C<'a> {
    C { pd }
}

#[derive(Debug)]
struct D<'a> {
    sd: &'a mut C<'a>,
}

fn init_d<'a>(sd: &'a mut C<'a>) -> D<'a> {
    D { sd }
}

fn main() {
    let mut a = init_a();
    let mut b = init_b(&mut a);
    let mut c = init_c(&mut b);

    let d = init_d(&mut c);

    println!("{:?}", d)
}
warning: variable does not need to be mutable
  --> src/main.rs:40:9
   |
40 |     let mut c = init_c(&mut b);
   |         ---^^
   |         |
   |         help: remove this `mut`
   |
   = note: #[warn(unused_mut)] on by default

Removing the mut causes a compiler error:

error[E0596]: cannot borrow immutable item `c` as mutable
  --> src/main.rs:42:20
   |
42 |     let d = init_d(&mut c);
   |                    ^^^^^^ cannot borrow as mutable

Metadata

Metadata

Assignees

No one assigned

    Labels

    A-NLLArea: Non-lexical lifetimes (NLL)A-diagnosticsArea: Messages for errors, warnings, and lintsC-bugCategory: This is a bug.E-mentorCall for participation: This issue has a mentor. Use #t-compiler/help on Zulip for discussion.NLL-diagnosticsWorking towards the "diagnostic parity" goalT-compilerRelevant to the compiler team, which will review and decide on the PR/issue.

    Type

    No type

    Projects

    No projects

    Relationships

    None yet

    Development

    No branches or pull requests

    Issue actions