Description
It turns out that an inner static is only generated once. Hence if you have a generic function and the static somehow takes the generic type into account, the static will have the same address for all instantiations. Turns out this is a soundness problem with TLS:
use std::local_data;
fn foo<T>() -> local_data::Key<T> {
local_data_key!(foo: T);
return foo;
}
fn main() {
let k1 = foo::<int>();
let k2 = foo::<float>();
local_data::set(k1, 1);
local_data::set(k2, 1f);
println!("{:#x}", local_data::get(k1, |x| *x.unwrap()));
println!("{}", local_data::get(k2, |x| *x.unwrap()));
}$ rust run foo.rs
warning: no debug symbols in executable (-arch x86_64)
0x3ff0000000000000
1
Notably, the inner static foo has the same address each time the function foo is instantiated, hence k1 and k2 are the same value, so the first local_data::get is actually printing the hex representation of 1f.
Naturally this allows arbitrary coercion of types via TLS in safe code, this is a definite soundness issue.
You can't declare inner functions with the type parameters declared in outer functions, so perhaps the same rule should apply to statics as well? If not, then this is a codegen problem.