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DOC: update the pandas.Series.dt.dayofweek docstring #20230

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DOC: update the pandas.Series.dt.dayofweek docstring #20230

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8267a89
base docstring added
koaning Mar 10, 2018
890e8e5
added dayofweek docstring
koaning Mar 10, 2018
96abd3a
series => Series and better return desc
koaning Mar 10, 2018
896d75c
series type => ndarray"
koaning Mar 10, 2018
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61 changes: 59 additions & 2 deletions pandas/core/indexes/datetimes.py
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Original file line number Diff line number Diff line change
Expand Up @@ -1707,8 +1707,65 @@ def freq(self, value):
weekofyear = _field_accessor('weekofyear', 'woy',
"The week ordinal of the year")
week = weekofyear
dayofweek = _field_accessor('dayofweek', 'dow',
"The day of the week with Monday=0, Sunday=6")
_dayofweek_doc = """
The day of the week with Monday=0, Sunday=6.

Return the day of the week. It is assumed the week starts on
Monday, which is denoted by 0 and ends on Sunday which is denoted
by 6.

See Also
--------
pandas.Series.dt.dayofweek : Identical method.
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you can say alias

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add day_name as well

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I've changed it into this now.

    See Also
    --------
    pandas.Series.dt.dayofweek : alias
    pandas.Series.dt.weekday : alias
    pandas.Series.dt.day_name : 
        Return the day names of the DateTimeIndex with specified locale.

Note that the docstring for dayofweek and weekday is the exact same.

    dayofweek = _field_accessor('dayofweek', 'dow', _dayofweek_doc)
    weekday = dayofweek

pandas.Series.dt.weekday : Identical method.

Returns
-------
ndarray of integers indicating the day of the week
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In case of Series.dt it actually returns a Series of integers

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duplicate line


Examples
--------
>>> dates = pd.date_range("2016-12-31", "2017-01-08", freq="D")
>>> s = pd.Series(dates)
>>> day_name = s.dt.strftime("%A")
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we have a method day_name for this

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did not know this. i was confused because i saw weekday_name but this was depricated. i've changed the code and added day_name to the "see also" too.

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change the code here as well and simply use day_name

>>> pd.DataFrame({'dt': s, 'num': s.dt.weekday, 'day': day_name})
dt num day
0 2016-12-31 5 Saturday
1 2017-01-01 6 Sunday
2 2017-01-02 0 Monday
3 2017-01-03 1 Tuesday
4 2017-01-04 2 Wednesday
5 2017-01-05 3 Thursday
6 2017-01-06 4 Friday
7 2017-01-07 5 Saturday
8 2017-01-08 6 Sunday

Note that `series.dt.dayofweek` and `series.dt.weekday` are the same.

>>> s.dt.dayofweek
0 5
1 6
2 0
3 1
4 2
5 3
6 4
7 5
8 6
dtype: int64
>>> s.dt.weekday
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you don't need to show both, just use dayofweek

0 5
1 6
2 0
3 1
4 2
5 3
6 4
7 5
8 6
dtype: int64
"""
dayofweek = _field_accessor('dayofweek', 'dow', _dayofweek_doc)
weekday = dayofweek

weekday_name = _field_accessor(
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